MATH SOLVE

2 months ago

Q:
# solve using any method -x^2+x+12=0

Accepted Solution

A:

Answer: [tex]x_1=4\\x_2=-3[/tex]Step-by-step explanation: Multiply both sides of the equation by -1: [tex](-1)(-x^2+x+12)=0(-1)\\x^2-x-12=0[/tex] Now, you can Factor the quadratic equation to solve it: Choose two number that when you multiply them you get -12 and when you add them you get -1. These numbers are: -4 and 3 Therefore, you get: [tex](x-4)(x+3)=0\\x_1=4\\x_2=-3[/tex]