Q:

Data on pull-off force (pounds) for connectors used in an automobile engine application are as follows:79.9 75.1 78.2 74.1 73.9 75.0 77.6 77.3 73.8 74.6 75.5 74.0 74.775.9 72.6 73.8 74.2 78.1 75.4 76.3 75.3 76.2 74.9 78.0 75.1 76.8(a) Calculate a point estimate of the mean pull-off force of all connectors in the population (Round the answer to four decimal places (e.g. 90.2353).)(b) Calculate a point estimate of the pull-off force value that separates the weakest 50% of the connectors in the population from the strongest 50% (Express the answer to two decimal place (e.g. 90.15).)

Accepted Solution

A:
Answer:a) 75.62b) 75.2Step-by-step explanation:Data provided:79.9,75.1,78.2,74.1,73.9,75.0,77.6,77.3,73.8,74.6,75.5,74.0,74.7,75.9,72.6,73.8,74.2,78.1,75.4,76.3,75.3,76.2,74.9,78.0,75.1,76.8Sum = 1966.3Total number of observations, n = 26a) Mean is given as:Mean = [tex]\frac{\textup{Sum of all observations}}{\textup{Total number of observations}}[/tex]orMean = [tex]\frac{\textup{1966.3}}{\textup{26}}[/tex]orMean = 75.62b) For value that separates the weakest 50% of the connectors i.e median or the 50th percentileArranging the data in ascending order: 72.6, 73.8, 73.8, 73.9, 74, 74.1, 74.2, 74.6, 74.7, 74.9, 75, 75.1, 75.1, 75.3, 75.4, 75.5, 75.9, 76.2, 76.3, 76.8, 77.3, 77.6, 78, 78.1, 78.2, 79.9i = [tex]\frac{\textup{n}}{\textup{2}}[/tex]ori = [tex]\frac{\textup{26}}{\textup{2}}[/tex]  = 13When the number of observations is even the formula for median is:[tex]Median = \frac{\frac{n}{2}+\frac{n+2}{2}}{2}[/tex]or[tex]Median = \frac{\frac{26}{2}+\frac{26+2}{2}}{2}[/tex]or[tex]Median = \frac{13th+14th}{2}[/tex]or[tex]Median = \frac{75.1+75.3}{2}[/tex]orMedian = 75.2